JEE Advanced Cut off 2020- The cut off for JEE Advanced 2020 will be released after the conduct of the JEE Advanced 2020 exam. The exam is expected to be held in the month of May 2020, tentatively and the result for the same will get released in the month of June 2020, tentatively. This national level exam is conducted to offer admissions to the aspiring candidates under various undergraduate Engineering, Sciences, and Architecture courses. The JEE Advanced 2020 exam will be conducted after the conduct of the JEE Main 2020 exam. The exam will be conducted by one of the seven zonal coordinating IITs. The Indian Institute of Technology will conduct the exam under the guidance of the Joint Admission Board (JAB). Read the complete article to get all the information regarding JEE Advanced Cut Off 2020.
The cut off for the JEE Advanced 2020 exam is the minimum marks required by the candidates in order to be eligible for admissions in any of the IIT. The aspiring candidates will need to either score more or equal marks than the last rank stated in the cut off for the exam. The conducting authority will release the JEE Advanced Cut off 2020 after the declaration of the result for the exam. The conducting body will prepare a rank list on the basis of the marks obtained by the candidates in the exam. Based on the cut off and rank list candidates will get admissions at ISM, Dhanbad, and IITs.
JEE Advanced Cut Off 2020
The cut off for JEE Advanced 2020 will be released after the release of the result for the exam. The JEE Advanced result 2020 is expected to release in the month of June 2020, tentatively. The result will be released online on the official website. The candidates will need to log on to the result portal using their login credentials. After the declaration of the JEE Advanced 2020 cut off and results, JoSAA will conduct the JEE Advanced counselling 2020. The Joint Seat Allocation Authority will manage all the activities related to the online counselling.
What are the factors affecting JEE Advanced Cut off 2020?
- Total number of candidates qualifying JEE Main 2020
- Total number of candidates applying for JEE Advanced 2020 exam
- Total number of candidates appearing for the exam
- Level of difficulty of the exam
- Previous year cut-off trends
JEE Advanced Previous Year Cut Off
Below here we have mentioned the previous year cut off of the JEE Advanced exam for your reference. We will update here the JEE Advanced cut off 2020 as soon as it is released by the authority.
| Category | Rank List | Minimum Marks (Each Subject) | Minimum Aggregate Marks | PwD Status |
| Any | CRL | 12 | 1128 | Any |
| Any | CRL-PwD | 6 | 64 | Yes |
| OBC-NCL | OBC-NCL | 10 | 115 | Any |
| OBC-NCL | OBC-NCL-PwD | 6 | 64 | Yes |
| Any | PC-CRL-PwD | 3 | 32 | Yes |
| OBC-NCL | PC-OBC-NCL-PwD | 3 | 32 | Yes |
| SC | PC-SC | 3 | 32 | Any |
| SC | PC-SC-PwD | 3 | 32 | Yes |
| SC | SC | 6 | 64 | Any |
| SC | SC-PwD | 6 | 64 | Yes |
| ST | ST | 6 | 64 | Any |
| ST | ST-PwD | 6 | 64 | Yes |
We advise you to also go through the previous year criteria for inclusion in the rank list in the JEE Advanced exam.
| Rank List | Minimum percentage of marks in each subject | Minimum percentage of aggregate marks |
| Common rank list (CRL) | 10.0 | 35.0 |
| Common-PwD rank list (CRL-PwD) | 5.0 | 17.5 |
| OBC-NCL rank list | 9.0 | 31.5 |
| OBC-NCL-PwD rank list | 5.0 | 17.5 |
| Preparatory course rank list | 2.5 | 8.75 |
| SC rank list | 5.0 | 17.5 |
| SC-PwD rank list | 5.0 | 17.5 |
| ST rank list | 5.0 | 17.5 |
| ST-PwD rank list | 5.0 | 17.5 |
Aspiring candidates willing to appear in the JEE Advanced 2020 exam are informed that they will need to score a minimum percentage of marks in order to be eligible for admissions based on their ranks. Below here we have mentioned the minimum marks required by candidates both subject and aggregate wise.
| Maximum aggregate marks (372) | Paper 1 (186) | Paper 2 (186) |
| Physics (124) | 62 | 62 |
| Chemistry (124) | 62 | 62 |
| Mathematics (124) | 62 | 62 |
JEE Advanced Cut Off 2020 – Rank List
The minimum marks required for qualifying in the rank list and the cut off for the JEE Advanced exam are both different things. Each of the seven IITs will release its own separate opening and closing ranks to offer admissions to the aspiring candidates. Below here we have provided the tabular representation of the previous year closing and opening ranks of different IITs.
| Institutions | Opening Rank | Closing Rank |
| IIT (BHU) Varanasi | 500 | 9805 |
| IIT Bombay | 1 | 4880 |
| IIT Delhi | 24 | 5431 |
| IIT Gandhinagar | 493 | 6869 |
| IIT Guwahati | 406 | 8000 |
| IIT Hyderabad | 418 | 6844 |
| IIT Indore | 933 | 7732 |
| IIT Jammu | 4743 | 6219 |
| IIT Kanpur | 113 | 7469 |
| IIT Kharagpur | 138 | 6312 |
| IIT Madras | 62 | 5319 |
| IIT Patna | 1541 | 7891 |
| IIT Roorkee | 294 | 7531 |
| ISM Dhanbad | 1655 | 9530 |
Top 20 Percentile – JEE Advanced Cut Off 2020 Marks
- The cut off marks for top 20 percentile category wise will be based on the scores secured by the qualifying candidates in the particular year from their respective boards.
- Candidates who have qualified their 12th class or any equivalent exam in 2020 will be considered in top 20 percentile cut off.
- The cut off for top 20 percentile will be considered of 2019 for the candidates who have qualified their 12th class in 2019 but will be appearing for improvement in 2020
The candidates will need to produce a certificate stating that he falls in the top 20 percentile of successful candidates from their respective board, in case the board doesn’t provide any information regarding the cut off of top 20 percentile. The cut off marks specified by the CBSE board will be considered final in case the candidate fails to do this.
